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Efficiency Based on Free-Energy Instead of Isentropic Conditions

[+] Author Affiliations
William Ernest Schenewerk

CA Nuclear Engineer NU 2272, Los Angeles, CA

Paper No. ICONE20-POWER2012-54971, pp. 867-872; 6 pages
doi:10.1115/ICONE20-POWER2012-54971
From:
  • 2012 20th International Conference on Nuclear Engineering and the ASME 2012 Power Conference
  • Volume 4: Codes, Standards, Licensing, and Regulatory Issues; Fuel Cycle, Radioactive Waste Management and Decommissioning; Computational Fluid Dynamics (CFD) and Coupled Codes; Instrumentation and Controls; Fuels and Combustion, Materials Handling, Emissions; Advanced Energy Systems and Renewables (Wind, Solar, Geothermal); Performance Testing and Performance Test Codes
  • Anaheim, California, USA, July 30–August 3, 2012
  • Conference Sponsors: Nuclear Engineering Division, Power Division
  • ISBN: 978-0-7918-4498-4
  • Copyright © 2012 by ASME

abstract

Traditional Isentropic-Eta method bases actual work on reversible work: ΛS = 0. Proposed Free-Energy-Eta method bases actual work on Gibbs Free-Energy change:

   ΛG = ΛH − T* ΛS.

T is exit stream temperature, causing Free-Energy-Eta results to match Isentropic-Eta results at unity efficiency.

   Free-Energy-Eta method for an engine:

   Free-Energy-Eta = (Actual Work Output) / (ΛG);

   Engine-Sout = (Hin − Hout) * (1 − Free-Energy-Eta) / (Free-Energy-Eta * Tout) + Sin.

As Turbine Free-Energy-Eta goes to 0, (Hin − Hout) goes to 0, keeping results finite.

   Free-Energy-Eta method for a fluid driver:

   Free-Energy-Eta = ΛG / (Actual Work Input);

   Driver-Sout = (Hout − Hin) * (1 − Free-Energy-Eta)/ Tout + Sin.

As driver Free-Energy-Eta goes to 0, Sout goes to (Hout − Hin)/ Tout + Sin. For an air compressor (driver), zero Free-Energy-Eta corresponds to ∼0.3 Isentropic-Eta.

Copyright © 2012 by ASME

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